Math, asked by anshuljamna786, 4 months ago

1 / Sec A + Tan A - 1/cos A = 1/cos A + 1/Sec A - tan A​

Answers

Answered by riyaverma62
1

Step-by-step explanation:

LHS = 1/seca – tana – 1/cosa

= cosa /(1- sina) – 1/cosa = (cos^2a – (1 – sina))/(1 – sina)(cosa)

= (sina – sin^2a)/(1 – sina)(cosa)

= (sina)(1 – sina)/(1 – sina)(cosa)

= tana

RHS = 1/cosa – 1/(seca+tana) = (1/cosa) –(cosa/(sina+1))

= (sina +1 – cos^2a)/(cosa)(sina+1)

= (sina +1 +sin^2a – 1)/(sina+1)(cosa)

= sina/cosa

= tana

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