Question

1/sec A - tan A = sec A + tan A​

Answer 1

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1/Sec theta - Tan theta = Sec theta + Tan theta

We have,

LHS = 1/Sec theta - Tan theta

=> 1/Sec theta - Tan theta × (Sec theta+Tan theta)/(Sec theta+Tan theta)

=> (Sec theta+Tan theta)/(Sec²thta-Tan²theta)

=> Sec theta + Tan theta = RHS

Hence, Proved