1+sec/secA=sin2A/1_cosA
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Answered by
8
Solution: (1 + secA)/secA
→ (1 + 1/cosA)/(1/cosA)
→ (1 + cosA)/cosA × cosA
→ 1 + cosA
Multiplying by (1 - cosA)/(1 - cosA)
→ (1 + cosA)(1 - cosA)/(1 - cosA)
→ (1 - cos²A)/(1 - cosA)
Identity: 1 - cos²A = sin²A
→ sin²A/(1 - cosA)
Q.E.D
Answered by
3
If its not square please tell that its sin2A
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