Question

1+sec-tan/1+sec+tan=1-sin/cos​

Answer 1

Answer:

So here L.H. S is equal to R.H.S....Proved

Step-by-step explanation:

Sol:-L.H.S = 1 + secA – tanA/1+ secA + tanA , R.H.S =1- sinA / cosA

= L.H.S(sec2A – tan2A) + secA tanA / 1

+ secA + tanA

As we know that [sec2A - tan2A = 1]

Here, L. H. S= (secA – tanA) (secA + tanA) + (secA – tanA) /1 + secA + tanA

L.H.S = (secA – tanA) (1+secA + tanA) /1+ =

secA + tanA

L.H.S = secA – tanA

We know about the formula of secA and tanA,[secA = 1 / cosA], [ tanA = sinA / =

cosA]

putting the value of secA and tanA

so = 1/cosA - sinA / COSA

L.H. S= 1 - sinA / cosA

So here L.H. S is equal to R.H.S....Proved

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