Math, asked by estherjoseph6828, 1 month ago

1 + sec theta /sec theta = sin2 theta /1-cos theta

Answers

Answered by johandamian776
6

Step-by-step explanation:

First, we consider

secθ

1+secθ

=

cosθ

1

1+

cosθ

1

=

cosθ

(cosθ+1)

(cosθ)

=1+cosθ

=(1+cosθ)×

(1−cosθ)

(1−cosθ)

=

1−cosθ

1−cos

2

θ

=

1−cosθ

sin

2

θ

.

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