Question

1 + sec theta - tan theta / 1 + sec theta + tan theta = 1- sin theta / cos theta

Answer 1

find the attachment

Answer 2

$\frac{1 + sec \theta - tan \theta}{1 + sec \theta + tan \theta} \\ \\ = \frac{( {sec}^{2} \theta - {tan}^{2} \theta) + (sec \theta - tan \theta) }{1 + sec \theta + tan \theta} \\ \\ = \frac{(sec \theta - tan \theta)(sec \theta + tan \theta + 1)}{1 + sec \theta + tan \theta} \\ \\ = sec \theta - tan \theta \\ \\ = \frac{1 - sin \theta}{cos \theta}$