Question

1 - sec theta +tan theta / 1 + sec theta - tan theta = sec theta + tan theta -1 / sec theta + tan theta +1​

Answer 1

Answer:

A boat leaves point P on one side of a river bank and travels with constant

velocity V in a direction towars point Q on the other side of the river directly

oposite P and distance D from it If r is the instantaneous distance from Q to the boat,

θ is the angle between r, and PQ, and the river travel with speed v, prove that the path of the boat

is given by

r=D*sec(θ)/(sec(θ)+tan(θ))^(V/v)

P

...................

|.

| .

| . --> v

D X

| .

| .

| .

|θ . V

| .

..................

¨ Q

Murray Spiegel 1.144

Answer 2

Answer:

Your answer attached in the photo