Question

1/sec theta - tan theta = sec theta + tan theta​

Answer 1

$\frac{1}{sec \theta - tan \theta} \\ \\ rationalizing \: the \: denominator \\ \\ = \frac{1}{sec \theta - tan \theta} \times \frac{sec \theta + tan \theta}{sec \theta + tan \theta} \\ \\ = \frac{ {sec} \theta + tan \theta}{ {sec}^{2} \theta - {tan}^{2} \theta } \\ \\ = sec \theta + tan \theta$