Math, asked by rairakshanda3225, 1 year ago

1/secA-1+1/secA+1=2cosecA.cotA

Answers

Answered by sandy1816

5

Step-by-step explanation:

1/secA-1 + 1/secA+1

=secA+1+secA-1/(sec²A-1)

=2secA/tan²A

=2 × 1/cosA × cos²A/sin²A

=2×cosA/sinA×1/sinA

=2cotAcosecA

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