1/seca+1-cosa/sin^2a=COSA/sin^2-1/seca-1
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Answer:
To prove :
secA
1+secA
=
1−cosA
sec
12
A
LHS
secA
1+secA
=
cosA
1
1+
cosA
1
=
cosA
1
cosA
cosA+1
=
cosA
cosA+1
×
1
cosA
=1+cosA
=1+cosA×
1−cosA
1−cosA
=
1−cosA
(1)
2
−(cosA)
2
=
1−cosA
1−cos
2
A
=
1−cosA
sin
2
A
=RHS
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