Question

1+secA /sec A =sin^A/1-cos A

Answer 1

Answer:

Here's your answer

Refer to the attachment .....

Hope it helps ✌✌....

Answer 2

Answer:

take RHS

1+secA/secA

1+ 1/cosA /1/cosA (:. secA =1/cosA)

cosA+1/cosA/ 1/cosA

cosA and CosA will be cancelled because thet are in division

therefore by cancellit cosA the result will be cosA +1

Now take LHS

sin^A/1-cosA -------(1)

we know that sin^A +cos^A = 1

sin^A =1-cos^A ------(2)

put value of sin^A from equation 2 to equation 1

therefore 1-cos^A/1-cosA

if we give square to 1 nothing will be changed.so we give square to one

=> 1^ - cos^A/ 1-cosA

now by identity a^-b^ =( a+b)(a-b)

here a^-b^ is 1^ -cos^A

=> (1-cosA)(1+cosA)/(1-cosA)

1-cosA will be cancelled

=> 1+cosA

hence LHS=RHS

hence proved

hope done .......it take sooo much time to write please add this in brain list..