Question

1+ SecA /Sec A=Sin square A / 1- CosA

Answer 1

Step-by-step explanation:

(1+ SecA )/Sec A=Sin²A / (1- CosA)

(1+1/CosA)/(1/cosA)=(1-cos²A)/(1-cosA)

(cosA+1)/cosA × cosA/1= (1+cosA)(1-cosA)/(1-cosA)

cosA+1=cosA+1

LHS=RHS proved