Question

(1+secA)/secA = 2cos^2(A/2)​

Answer 1

Step-by-step explanation:

cos2A = 2cos^2A - 1

cosA = 2 cos^2 A/2 - 1 -- (1)

1+secA/secA

= cosA[1+(1/cosA)]

= cosA + 1

= (2cos^2 A/2 - 1) + 1 --- from (1)

= 2cos^2 A/2 ( proved