Math, asked by safaamtul22, 1 year ago

1+secA/secA=sin squareA/1-cosA

Answers

Answered by Manikumarsingh

LHS=1+secA/secA
= (1+1/cosA)/1/cosA
1+cosA
---------- × cosA
cosA

1+cosA

RHS= sin^2A/1-cosA
1-cos^2A/1-cosA

(1-cosA)(1+cosA)
------------------------
(1-cosA)

(1+cosA)

therefore, LHS=RHS

safaamtul22: Thank u my friend

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