Math, asked by Sunithagreeshma77, 2 months ago

1+secA /secA = sin2^A/1-cosA

Answers

Answered by ashu0itkm

0

Answer:

(cosA+1) (1-cosA) =sin2a

1-cos2A=

sin2A

lhs=rhs

Answered by harshitabohra

1

Refer to the image attached for detailed solution.

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