Question

1+ secA / secA = Sin²A/ 1- Cos A​

Answer 1

Answer:

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Answer 2

Answer:

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Step-by-step explanation:

To prove :

secA

1+secA

=

1−cosA

sec

12

A

LHS

secA

1+secA

=

cosA

1

1+

cosA

1

=

cosA

1

cosA

cosA+1

=

cosA

cosA+1

×

1

cosA

=1+cosA

=1+cosA×

1−cosA

1−cosA

=

1−cosA

(1)

2

−(cosA)

2

=

1−cosA

1−cos

2

A

=

1−cosA

sin

2

A

=RHS