1+secA/secA=sin²A/1-cosA
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(1+secA)/secA=sin²A/(1-cosA)
Taking L.H.S
(1+secA)/secA
1/secA+secA/secA
cosA+1
Multiplying and dividing by 1-cosA
((1+cosA)(1-cosA))/(1-cosA)
(1-cos²A)/(1-cosA)
But 1-cos²A= sin²A
sin²A/(1-cosA)
L.H.S=R.H.S
Hence Proved
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