Question

1+secA/secA=sin²A/1-cosA​

Answer 1

Answer:

Do you want me to prove it...

Step-by-step explanation:

To prove :

secA

1+secA

=

1−cosA

sec

12

A

LHS

secA

1+secA

=

cosA

1

1+

cosA

1

=

cosA

1

cosA

cosA+1

=

cosA

cosA+1

×

1

cosA

=1+cosA

=1+cosA×

1−cosA

1−cosA

=

1−cosA

(1)

2

−(cosA)

2

=

1−cosA

1−cos

2

A

=

1−cosA

sin

2

A

=RHS