Question

1+secA/secA=sin2A/1-cosA simplify LHS and RHS separately​

Answer 1

Step-by-step explanation:

LHS

1+sec A

------------–

secA.

1 + 1

————

cosA

—————————

1

———-

cos A

cosA+1

——--——

cosA

————-—

1

——-—-

cos A

cosA+1

RHS

sin2A

—————

1-cos cos A

1 - cos2A

—————-——

1-cos A

(1 - cos A ) (1 + cos A )

————-————————

(1 - cos A)

cos +1

Hence LHS = RHS

Hence proved