Question

1/(secA + tan
A) is equal to

Answer 1

Answer:

please Mark as brilliant answer

Answer 2

Step-by-step explanatio\frac{1}{ \sec(a) + \tan(a) } \\ = \frac{1}{ \frac{1}{ \cos(a) + \frac{ \sin(a) }{ \tan(a) } } \\ = \frac{1}{ \frac{1 + \sin(a) }{ \cos(a) } } \\ = \frac{ \cos(a) }{1 + \sin(a) } [/tex]