(1/secA + tanA ) - (1/cosA) = (1/cosA) - (1/secA - tanA)
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Answered by
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aditi25494:
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Answered by
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Answer:
Step-by-step explanation:
LHS:- [ 1/secA + tanA ] - 1/cosA
=[ 1 (secA-tanA) / secA+tanA (secA-tanA) ] - secA
= [ secA - tanA / sec2A - tan2A ] -secA
=secA - tanA - secA
= - tanA
RHS:- 1/cosA - [ 1/secA - tanA ]
= secA - [1 (secA + tanA) / secA - tanA (secA + tanA) ]
= secA - (secA + tanA / sec2A - tan2A ]
= secA - ( secA + tanA )
= secA - secA - tanA
= - tanA
SO, LHS=RHS. Hence, proved.
Hope it helps
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