Question

1/secA-tanA - 1/cosA
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Answer 1

Answer:

the question is incomplete

Answer 2

Answer:

Given, secA−tanA1−cosA1=cosA1−secA+tanA1

or   secA−tanA1+secA+tanA1=cosA1+cosA1

Here, R.H.S.=cosA2

Now, 

L.H.S.=secA−tanA1+secA+tanA1=(secA−tanA)(secA+tanA)secA+tanA+secA−tanA=cosA2

Thus, L.H.S.=R.H.s

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