Math, asked by shekinahyimsung, 1 year ago

1/secA-tanA + 1/secA+tanA =2/cosA

Answers

Answered by shadowsabers03
6

       

\boxed{$LHS$} \\ \\ \boxed{\frac{1}{\sec A - \tan A}+\frac{1}{\sec A+\tan A}} \\ \\ \\ \boxed{\frac{\sec A +\tan A+\sec A -\tan A}{(\sec A-\tan A)(\sec A+\tan A)}} \\ \\ \\ \boxed{\frac{2\sec A}{\sec^2A-\tan^2A}} \\ \\ \\ \boxed{\frac{2\sec A}{1}} \\ \\ \\ \boxed{2 \sec A} \\ \\ \\ \boxed{2 \times \frac{1}{\cos A}} \\ \\ \\ \boxed{\frac{2}{\cos A}} \\ \\ \\ \boxed{$RHS$}

$$\sf{Hence proved! \\ \\ \\ Plz mark it as the brainliest. \\ \\ \\ Thank you. :-))}

       

Answered by preeti998
0

Answer:

Above is the correct answer

Step-by-step explanation:

But wrong order

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