Question

1/secA-tanA + 1/secA+tanA =2/cosA

Answer 1

       

$\boxed{ LHS } \\ \\ \boxed{\frac{1}{\sec A - \tan A}+\frac{1}{\sec A+\tan A}} \\ \\ \\ \boxed{\frac{\sec A +\tan A+\sec A -\tan A}{(\sec A-\tan A)(\sec A+\tan A)}} \\ \\ \\ \boxed{\frac{2\sec A}{\sec^2A-\tan^2A}} \\ \\ \\ \boxed{\frac{2\sec A}{1}} \\ \\ \\ \boxed{2 \sec A} \\ \\ \\ \boxed{2 \times \frac{1}{\cos A}} \\ \\ \\ \boxed{\frac{2}{\cos A}} \\ \\ \\ \boxed{ RHS }$

$\sf{Hence proved! \\ \\ \\ Plz mark it as the brainliest. \\ \\ \\ Thank you. :-))}$

       

Answer 2

Answer:

Above is the correct answer

Step-by-step explanation:

But wrong order