Math, asked by rockboypuneet58, 4 months ago

1/secA+tanA+1/secA-tanA=2sec A​

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Answered by nikhilsharma6674
0

Just Use The Property-

a {}^{3}  + b { }^{3}  = (a + b)(a {}^{2} +  b ^{2}  - ab)

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