Math, asked by denilpil153, 9 months ago

1/secA+tanA=1-sinA/cosA=secA-tanA

Answers

Answered by TħeRøмαи

4

Step-by-step explanation:

1/secA+tana=1-sina/cosA

1/1/cosa+sina/cosa=1-sina/cosa

1/1+sina/cosa=1-sina/cosa

cosa/1+sina=1-sina/cosa

cross multiply

cos^2a=1-sin^2a

cos^2a=cos^2a

LHS=RHS

hope its helpful

Answered by rohitsau

4

Answer:

here is the correct answer

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