Math, asked by tanujadsable1, 2 months ago

1+(secA-tanA)²/cosecA(secA-tanA)​

Answers

Answered by paudelsandhya27
0

Answer:

1+ (sec^2 A - 2secA tanA + tan^2 A) / cosecA ( secA - tanA) =

(1 + tan^2 A) + sec^2 A - 2secA tanA / cosecA ( secA - tanA) =

sec^2 A + sec^2 A - 2secAtanA / cosecA ( secA - tanA) =

Step-by-step explanation:

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