Math, asked by PratichiGhosal, 4 months ago

(1/ (secA + tanA) )= secA - tanA

Answers

Answered by vivekydv1109

0

Step-by-step explanation:

1/secA+tanA=secA-tanA

LHS=1/secA+tanA

=1/secA+tanA*secA-tanA/secA-tanA

=secA-tanA/sec^2A-tan^2A

=reciprocal

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