Question

1/(secA+tanA) = secA - tanA​

Answer 1

Step-by-step explanation:

$in \: second \: step \: multiply \\ \sec(A )- \tan(A) \: with \: both \\ \: numerator \: and \: denominator \:$

And,

${sec(A)}^{2} - { \tan(A) }^{2} = 1$