Math, asked by komal661164, 1 year ago

1/secA-tanA=secA+tanA

Answers

Answered by royal171gmailcom
1
the answer is completed
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Answered by NeverMind11
1
1/secA+tanA

Multiply by secA - tanA on both denominator and nominator

(secA - tanA) ÷ (sec²A - tan²A) 

We know, sec²A - tan²A = 1

Then, 

(secA - tanA) ÷ 1

SecA - tanA

NeverMind11: i hope this helps you
NeverMind11: ...
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