Math, asked by kniyamath15, 11 months ago

1 + seco
Show that
Sece-
sine
1-cos
sec @

Answers

Answered by ritiksen

1

Answer:

LHS = ( 1 + secA )/secA

= ( 1 + 1/cosA ) / ( 1/cosA )

= [ ( CosA + 1 ) / cosA ] / ( 1/ cosA )

= Cos A + 1

= ( 1 + cosA ) ( 1 - cosA ) / ( 1 - cosA )

= ( 1 - cos² A ) / ( 1 - cosA )

= Sin² A / ( 1 - cosA )

= RHS

Step-by-step explanation:

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