Question

1/secQ - tanq = secQ + tanQ. Prove

Answer 1

Step-by-step explanation:

• now we know that

1 / secQ - tanQ = secQ + tanQ

• so if we solve it further we will get

1 = ( secQ+ tanQ)( secQ-tanQ)

by using identity for a^2 - b^2

= (a+b)(a-b)

according to that

secQ^2- tanQ^2= 1

• Hence proved •

Extra info..

sec Q = h/b

sec Q^2= h^2/ b^2

and

tan Q = p/b

tanQ^2 = p^2/ b^2

now ( secQ^2-tanQ^2)= (h^2/ b^2) - (p^2 / b^2)

= (h^2- p^2) / b^2

= b^2 / b^2 =1