Question

1.
SECTION -A
For what value of k system of equations
x + 2y = 3 and 5x + ky +7 = 0 has a unique solution.
1​

Answer 1

Step-by-step explanation:

The given system of equations:

x + 2y = 3

x+2y-3=0

And, 5x + ky +7=0

.(i) ... (ii)

These equations are of the following form: a₁x + b₁y+c₁ = 0, a2x + b₂y + C₂ = 0 where,

1, b₁ = 2, c1 a1 = 6₁ -3 and a2 = 5, b₂ -

(i) For a unique solution, we must have:

a1 a2 b₁ 1 2 # Li.e., # ⇒k 10 b₂ k

Thus for all real values of k other than 10, the

given system of equations will have a unique

solution.