Physics, asked by MurariChaudhary, 10 months ago

1.
SECTION - A
Objective Type Questions
An electron is moving on a circular orbit of radius
r with speed v. It produces a magnetic field B at
its centre, then radius of circle is proportional to

Answers

Answered by aristocles
0

Answer:

the radius of the circle is inversely proportional to the square root of magnetic field

Explanation:

If an electron is moving in circular orbit of radius "r" with speed "v"

so the time period of the motion of the charge is

T = \frac{2\pi r}{v}

now the current due to circulation of charge is

i = \frac{Q}{T}

i = \frac{ev}{2\pi r}

now magnetic field at the center of the circle is given as

B = \frac{\mu_0 i}{2r}

plug in the value of current

B = \frac{\mu_0 ev}{4\pi r^2}

So the radius of the circle is inversely proportional to the square root of magnetic field

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Topic : Magnetic effect of current

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