Question

1+secx/secx = sin^2x/1-cos x
Prove LHS=RHS

Answer 1

Step-by-step explanation:

kom the same time as the one I have a look at the moment and I will be able to get the best way to get the best way to get the best way to get the best way to get the best way to get

Answer 2

Answer:

(1+ sec x) / sec x = (sin^2 x) / (1 - cos x) [ sin^2 x = 1 - cos^2 x]

(1+ sec x) / sec x = ( 1 - cos^2 x) / (1 - cos x)

(1+ sec x) / sec x = (1 + cos x) (1 - cos x ) / ( 1 - cos x) [ a^2 - b^2 = (a+b) (a-b)]

will be canceled

(1+ sec x) / sec x = (1 + cos x)

(1+ sec x) = sec x +(cos x ) (sex x)

will be canceled [cos x = 1/sec x]

1 + sec x = sec x + 1

===> LHS = RHS

hence proved.....

I hope it will help.....