Question

1/secx+tanx - 1/cosx=1/cosx-1/secx-tanx

Answer 1

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Answer 2

$\frac{1}{secx - tanx} - \frac{1}{cosx} \\ \\ = secx + tanx - secx \\ \\ = secx - (secx - tanx) \\ \\ = \frac{1}{cosx} - \frac{1}{secx + tanx}$