Math, asked by Abhishekpandey3843, 11 months ago

1/secx-tanx- 1/cosx= 1cosx-1/secx+tanx

Answers

Answered by spiderman2019
0

Answer:

Step-by-step explanation:

L.H.S:

//multiply the numerator and denominator of 1/secx-tanx with (secx+tanx)

secx+tanx/(secx-tanx)(secx+tanx) -  1/cosx

= secx+tanx/sec²x - tan²x - secx

//remember sec²x - tan²x = 1

= secx + tanx - secx = tanx.

R.H.S:

//multiply the numerator and denominator of 1/secx+tanx with (secx-tanx)

= 1/cosx - (secx -tanx)/(secx+tanx)(secx-tanx)

= 1/cosx - (secx -tanx) / sec²x - tan²x

//remember sec²x - tan²x = 1

= 1/cosx - (secx-tanx)

= secx - secx + tanx

= tanx.

L.H.S =R.H.S

Hence proved.

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