Question

1. Seema and Pooja borrowed 60,000 and 50,000 respectively for a period of 3 years. Seema
paid simple interest at the rate of 10% p.a., while Pooja paid compound interest at the rate of
10% p.a., compounded annually. Who paid more interest and by how much?
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Answer 1

Answer:

$\fcolorbox{red}{pink}{ \: hope \: so \: it \: will \: help \: you \: }$

$\fcolorbox{blue}{cyan}{interest \: paid \: by \: seema}  </p><p></p><p>$

$= \frac{p \times r \times t}{100} = \frac{6000 \times 3 \times10}{100}$

$\fcolorbox{blue}{cyan}{ = 18000}$

$\fcolorbox{blue}{cyan}{interest \: paid \: by \: pooja}$

$= p(({1 + \frac{r}{100}})^{n} - 1)$

$= 50000(({1 + \frac{10}{100} })^{3} - 1)$

$= 50000( \frac{113}{163} - 1)$

$= 50000 \times \frac{331}{1000}$

$= 16550$

$\fcolorbox{red}{pink}{seema \: paid \: more \: interest \: se \: = 1450 \: }$

$\fcolorbox{red}{pink}{mark \: as \: brainlist}</p><p></p><p>$