Question

1.separate 132 into two parts such that it the longer is divided by the smaller the quotient is 6 and the remainder is 13?

Answer 1

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Answer 2

Answer:

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Step-by-step explanation:

the larger part, 132-x , is divided by the smaller, x, the quotient is 6 and the remainder is 13

means that 132-x , minus the 13 remainder, divided by x is exactly 6 :

6=%28132-x-13%29%2Fx

Solving:

6=%28132-x-13%29%2Fx-->6=%28119-x%29%2Fx-->6x=119-x-->6x%2Bx=119-->7x=119-->x=119%2F7-->highlight%28x=17%29 .

Then 132-x=132-17-->highlight%28132-x=115%29

The two parts are highlight%2817%29