Question

1. Show that 3√2 is an irrational number.​

Answer 1

Answer:

• We have to prove this by contradiction method
• let us assume 3root2 as an rational number
• therefore 3root2 =p/q
• root2=p/3q
• here p/3q is a rational number but root 2 is a irrational number so our assumption is wrong
• therefore 3root2 is an irrational no.

Answer 2

Answer:

Step-by-step explanation: If possible let 3√2 be rational.Then,

3√2 is rational,1/3 is rational

= (1/3*3√2)is rational    [ because produc of two number is rational ]

  = √2 is rational.

 This contradicts the fact that √2 is irrational.

    The contradict arises by assuming that 3√2 is rational.

Hence,  3√2 is irrational.