1. show that length AH > AB + BC + CD.
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Answers
Answered by
4
Answer:
AH=AB+BC+CD+DE+EF+FG+GH
⇒AB+BC+CD is a part of AH
According to Euclid's fifth axiom the whole thing is greater then a part
∴AH>AB+BC+CD
Answered by
10
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