1.) Show that none of the following is an identity :
I. cos² 0 + cos 0 = 1
ii. sin²0 + sin 0 = 2
iii. tan ² 0 + sin 0 = cos²0
2.)
PLEASE ANY ONE SOLVE THIS QUESTION WITH EXPLANATION...
Answers
Step-by-step explanation:
To proof none of them is an identity, we need to put a value in the place of θ so that we can compare the LHS and RHS.
Thus, let's say θ = 60°.
Hence,
I. cos² θ + cos θ = 1
cos² 60 + cos 60 = 1;
(1/2)^2 + (1/2) = 1;
1/4 + 1/2 = 1;
3/4 ≠ 1;
Thus, cos² θ +cos θ= 1, is not an identity because it should've worked for every value (0 ≤ θ ≥ 90) of θ.
Here, let θ be 30°.
Hence,
II. sin² θ + sin θ = 2;
sin² 30 + sin 30 = 2;
(1/2)^2 + (1/2) = 2;
1/4 + 1/2 = 2;
3/4 ≠ 2;
Thus, sin² θ +sin θ= 2 is not an identity because it should've worked for every value (0 ≤ θ ≥ 90) of θ.
Here, let θ be 0°.
Hence,
III. tan ² θ + sin θ = cos² θ;
tan ² 0 + sin 0 = cos² 0;
0 + 0 = 1.
0 ≠ 1.
Thus, tan² θ +sin θ=cos² θ, is not an identity because it should've worked for every value (0 ≤ θ ≥ 90) of θ.
2. (cos θ.cosec θ - sin θ.secθ)/(cos θ +sin θ) = cosec θ - sec θ;
= (cos θ.(1/sin θ) - sin θ.(1/cosθ))/(cos θ +sin θ) = (1/sin θ) - (1/cos θ);
= (cos θ/sin θ - sin θ/ cos θ)/(cos θ +sin θ) = (cos θ - sin θ)/cos θ.sinθ;
= ((cos^2 θ - sin^2 θ)/sinθ.cos θ)/(cos θ +sin θ) = (cos θ - sin θ)/cos θ.sinθ;
= ((cos^2 θ - sin^2 θ))/(sinθ.cos θ)(cos θ +sin θ) = (cos θ - sin θ)/cos θ.sinθ;
= ((cos^2 θ - sin^2 θ))/(cos θ +sin θ) = (cos θ - sin θ);
= ((cos^2 θ - sin^2 θ))/(cos θ +sin θ) = (cos θ - sin θ);
= ((cos θ - sin θ)(cos θ +sin θ))/(cos θ +sin θ) = (cos θ - sin θ); (since, a^2 - b^2 =(a+ b)(a -b))
= (cos θ - sin θ) = (cos θ - sin θ);
Thus. LHS = RHS.
That's all.
2.) cos theta × cosec theta- sin theta × sec theta/ cos theta + sin theta = cosec theta- sec theta
Step- by- step explanation:-
Ans) cos theta ×1/sin theta- sin theta ×1/cos theta÷ cos theta + sin theta
cos theta/ sin theta- sin theta/ cos theta ÷ cos theta + sin theta
cos ^2 theta- sin ^2 theta/ sin theta × cos theta ÷ cos theta +sin theta/1
cos ^2 theta- sin ^2theta/sin theta. cos theta ×1/cos theta + sin theta
cos ^2 theta- sin ^2/sin theta. cos theta (cos theta +sin theta)
(cos theta- sin theta)(cos theta +sin theta )/ sin theta. cos theta (cos theta +sin theta)
(cos theta- sin theta)/sin theta. cos theta
cos theta/ sin theta. cos theta- sin theta/ sin theta. cos theta
1/sin theta- 1/cos theta
cosec theta- sec theta . R.H.S