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tan A. sin A+cos A = sec A
D Dand
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Answer:
tan A.sin A+cosA = sec A
L.H.S
sinA.sinA/cosA+cosA
sin²A+cos²A/cosA
since,sin²A+cos²A =1 (by trigonometric identities)
therefore, 1/cosA= secA
L.H.S = R.H.S
hence proved
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