Question

1 show that (tan
A X Sin A) +COSA =
Sec A​

Answer 1

Answer:

L.H.S

(tanA*sinA)+cosA

(sinA/cosA*sinA)+cosA

(sinA^2+cos^2)/cosA

1/cosA

:(cosA^2+sinA^2=1)

secA=R.H.s

Answer 2

Answer:

(tan A . sinA)+cosA

((sinA/cosA)*sinA) +cosA

sin^2A/cosA + cosA

(sin^2A+cos^2A)/cosA

1/cosA

=secA

hence proved