Question

1. Show that the function x3 - 6x2 + 12x – 1 increases for all values
of x.​

Answer 1

Answer:

f(x)=x^3-6x^2+12x-18

f(x)=3x^2-12x+12

=3(x^2-4x+4)

=3(x-2)^2

=f(x)>0for all x€R

● f(x) is increasing for all on x€R