1. Show that the point (0, -1), (6, 7), (-2,3) and (8,
3) are the vertices of a rectangle.
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Step-by-step explanation:
Let the points of rectangale such that AB=CD and AD=BC are: A(0,-1), B(6,7),C(-2,3), D(8,3).
Distance=√(x2-x1)²+(y2-y1)².
Then:
AB=CD:
√(6-0)²+(7+1)²=√(-2-8)²+(3-3)²
√36+64=√100
√100units=√100units.
AD=BC:
√(8-0)²+(3+1)²=√(-2-6)²+(3-7)²
√8²+4²=√(-8)²+(-4)²
√64+16=√64+16.
√80units=√80units.
The opposite sides are equal.
Hence, the given points are vertices of a rectangle.
Hope helps u.
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1
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