Question

1.Show that the point (11,2) is the centre of the circle
passing through the points (1,2), (3,-4) and (5,-6)​

Answer 1

Answer:

Let equation of general equation of circle is x² + y² + 2gx + 2fy + c = 0 then, centre of circle will be (-g , - f)

Circle passing through three points (1,2) , (3,-4) and (5,-6) .

Put (1,2) in equation of circle.

1² + 2² + 2g(1) + 2f(2) + c = 0

2g + 4f + c + 5 = 0 -----(1)

Answer 2

Step-by-step explanation:

this is the answer of the question