(1) Show that the points A(0,0), B(4,4)
c (3,5) and D(-1,2) taken in
order form a peralelogram:
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no it is not in the order of parallelogram
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d(AB) = √(x2-x1)² + ( y2-y1)²
d(AB) = √(4-0)² + (4-0)²
d(AB) = √(4)² + (4)²
d(AB) = √16 + 16
d(AB) = √32
d(AB) = 4√2
d(BC) = √(x2-x1)² + (y2-y1)²
d(BC) = √(4-3)² + (5-4)²
d(BC) = √(1)² + (1)²
d(BC) = √1 + 1
d(BC) = √2
d(CD) = √(x2-x1)² + (y2-y1)2
d(CD) = √{(-1)-3}² + (5-2)²
d(CD) = √(4)² + (3)²
d(CD) = √16+9
d(CD) = √25
d(CD) = 5
d(AD) = √(x2-x1)² + (y2-y1)²
d(AD) = √{(-1)-0}² + (2-0)²
d(AD) = √(1)² + (2)²
d(AD) = √1 + 4
d(AD) = √5
There will be no order to form a parallelogram.
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