Question

1. Show that (x+1) is a factor of x^3-7x-6 and find the other factors?

Answer 1

Answer:

Other factors are (x-3) and (x+2)

Step-by-step explanation:

x³-7x-6

=x³+x²-x²-x-6x-6

=x²(x+1)-x(x+1)-6(x+1)

=(x+1)(x²-x-6)

=(x+1)(x²-3x+2x-6)

=(x+1)(x-3)(x+2)

Hence it is divisible by (x+1)