1) Side of an equilateral ABC is 8cm.Find the side of an equilateral PQR whose area is twice the area of the first
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8 ROOT 2 IS THE ANSWER
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According to question,
Area of ∆PQR =2× Area of ∆ABC
We know that,area of equilateral traingle is √3/4×(side)²
:.√3/4×(side)²=2×√3/4×(8)²
:.√3/4×(side)²=2×√3/4×64
:.√3/4×(side)²=2×√3×16
:.√3/4×(side)²=32√3
:.(side)²=32√3×4/√3
:.(side)²=32×4
:.(side)²=128
:.side=√128
:.Side=11.31cm
The side of an equilateral ∆PQR whose area twice the area of the first
is 11.31cm
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