Question

1) Side of an equilateral ABC is 8cm.Find the side of an equilateral PQR whose area is twice the area of the first​

Answer 1

Answer:

8 ROOT 2 IS THE ANSWER

Step-by-step explanation:

Answer 2

According to question,

Area of ∆PQR =2× Area of ∆ABC

We know that,area of equilateral traingle is √3/4×(side)²

:.√3/4×(side)²=2×√3/4×(8)²

:.√3/4×(side)²=2×√3/4×64

:.√3/4×(side)²=2×√3×16

:.√3/4×(side)²=32√3

:.(side)²=32√3×4/√3

:.(side)²=32×4

:.(side)²=128

:.side=√128

:.Side=11.31cm

The side of an equilateral ∆PQR whose area twice the area of the first

is 11.31cm

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