Question

1. Sides of a triangle are 72 cm, 38 cm and 45 cm. Its semi perimeter is​

Answer 1

Answer:

semiperimeter (s)=77.5 cm

Step-by-step explanation:

let the sides of ∆ be x, y and z respectively.

semiperimeter (s)=x + y + z

2

=72+38+45

2

=155/2

semiperimeter (s)=77.5 cm

Answer 2

$\Large\bold{\underline{\underline{Question:-}}}$

Sides of a triangle are 72 cm, 38 cm and 45 cm. Its semi perimeter is ?

$\Large\bold{\underline{\underline{Answer:-}}}$

Given that the three sides of triangle are 72cm, 38cm and 45cm.

As the semi-perimeter is the half of the sum of sides of triangles.

$s \: = \: \frac{a + b + c}{2} \\ \\ s \: = \frac{72 + 38 + 45}{2} \\ \\ s \: = \frac{155}{2} \\ \\ s \: = 77.5$

$\Large\bold{\underline{\underline{Answer \ is \ 77.5cm}}}$

Sides of a triangle are 72 cm, 38 cm and 45 cm. Its semi perimeter is 77.5cm.